Question

6) if Triangle ABC is right angled at C, cos (A + B) = ......
a. 0
b. 1
c. 1/3
d 1/2​

Answer 1

Answer:

Since ABC is a right angled triangle right angled at C

Hence

A+B=180

0

−C=90

0

Hence

cos(A+B)

=cos(90

0

)

=0

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Answer 2

Answer:

If C=90°

Therefore

cos(A+B)

=cos(180°−C)

=cos(180°−90°)

=cos(90°)

=0

Step-by-step explanation:

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