Question

6. If (x - 1) and (x + 3 ) are factors of polynomial f(x) = x3 – hx2 – 13x + k find the values of ‘
and 'k'
​

Answer 1

when x = 1

x ^3 - x ^2 - 13 x + k = 0

(1)^3 - (1)^2 - 13(1) +k = 0

1 - 1 - 13 + k = 0

0 - 13 + k = 0

k = 13

when x = -3 ( x+3=0)

x ^3 - x ^2 - 13 x + k = 0

(-3)^3 - (-3)^2 - 13 (-3) + k = 0 ( solving cube and squares of 3 )

-27 - 9 - 39 + k = 0

- 36 - 39 + k = 0

- 3 + k = 0

henxe , k = 3

regards mark me brainliest dear❤