Question

6. If x=2 and y=1, find the value
of (-4x^2y^3)(-5x^2y^5) ​

Answer 1

Answer:

As per the Question

(-4x^2×y^3)(-5x^2×y^5)

⇒{(-4×2^2)×1^3}×{(-5×2^2)×(y^5)}

⇒{-16×1}×{-20×1}

⇒-16×-20

⇒320

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