Question

6. If (x - y) = 11 and xy = 6, find the value of
x² + y²​

Answer 1

Answer:

we know that,

(x-y)^2=x^2+y^2-2xy

from the values

(11)^2+2*6=x^2+y^2

121+12

133

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Answer 2

Answer:

(x-y)²= x² + y² - 2xy

(11)² = x² + y² -2*6

121 = x² + y² - 12

x² + y² = 121 + 12

x² + y² = 133

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