Question

6. If (x - y) = 13 and xy = – 5, then find the value of ⅓x²+y²
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Answer 1

Step-by-step explanation:

x-y=13

xy=-5

1/3x²+y²=?

(x-y)^2=x²+y²-2xy

13^2=x²+y²-2*-5

169=x²+y²+10

x²+y²=169-10

x²+y²=159

1/3x²+y²

=159/3

=33