Question

6. If you are in a car that is being pulled down a 56.0 m path with a force of 12.5 N, what is the work done on the car? 56M

Answer 1

Given:

You are in a car that is being pulled down a 56.0 m path with a force of 12.5 N.

To find:

Work done on the car ?

Diagram:

$\setlength{\unitlength}{1cm}\begin{picture}(5,5)\put(1,1){\framebox(1,1){\sf{M}}}\put(2,1.5){\vector(1,0){2.1}}\put(4.4,1.4){\bf{F}}\put(0.5,1){\line(1,0){4.5}}\multiput(0.6,1)(0.22,0){20}{\qbezier(0,0)(-0.1,-0.1)(-0.2,-0.2)}\end{picture}$

Calculation:

Work done on an object is defined as the scalar product of the force vector and displacement vector of the object.

Since the force and displacement are directed in the same directions , hence we can say that:

$\rm \therefore \: W = force \times displacement$

$\rm \implies \: W = 12.5\times 56$

$\rm \implies \: W =700 \: joule$

So, the work done on the car is 700 joule