Question

6. Ifp = -2,q=-1 and r = 3, find
(i) p2 +q2-p2.
(iv) p3+q3+r3+3pqr ​

Answer 1

Answer:

(i) $p^{2}$ + $q^{2}$ - $r^{2}$ = -4

(iv) $p^{3}$ + $q^{3}$ + $r^{3}$ + 3pqr = 36

Step-by-step explanation:

Given that, p = -2, q = -1, and r = 3

(i) $p^{2}$ + $q^{2}$ - $r^{2}$ = $(-2)^{2}$ + $(-1)^{2}$ - $3^{2}$ = 4 + 1 - 9 = -4

(iv) $p^{3}$ + $q^{3}$ + $r^{3}$ + 3pqr = $(-2)^{3}$ + $(-1)^{3}$ + $3^{3}$ + 3.(-2).(-1).3 = -8 -1 + 27 + 18 = 36