Question

(6) IfZA= 2B = 90° and AQ = BQ = 3 cm, prove that:
(1) APAQ = APBQ
(1) PA = PB​

Answer 1

Answer:

Answer

Given AB is 3 cm,PR is 2 cm PR is 6 cm

In △PAB and △PQR

∠PAB=∠PQR (corresponding angles)

and ∠P is common.

∴△PAB∼△PQR (AA similarity criterion)

Since corresponding sides are proportional,

QR

AB

=

PR

PB

QR=

PB

AB×PR

=

2

3×6

Thus, QR=9 cm.