Question

6. In a bag, there are 5 red balls. 6 black balls and 9 blue balls. If a ball is drawn at random find the
probability of getting a) black ball
b) not red​

Answer 1

Step-by-step explanation:

ANSWER

Total no. of balls=4+6+3=13

Total no. of ways one ball out of 7,n(S)=13C1

No.of ways of drawing 1 ball,none of then is blue,n(E)=13−6=7C1

∴probability=n(S)n(E)=137

Answer 2

Step-by-step explanation:

(a) Total outcomes=20

    No. of favorable events= 6

     Probability= $\frac{6}{20}$ = $\frac{3}{10}$

(b) Total outcomes = 20

     No. of favorable events = 15

      Probability = $\frac{15}{20}$ = $\frac{3}{4}$