Question

6.
in a city it was found that the amount of daily deposit of pollutant is
3.2 x 109 g/cm². If the city has an area of 400 square kilometre and the pollutan
is distributed evenly, find the amount of pollutant that falls on the city.
(i) in one day
(ii) in one year

Answer 1

Answer:

Step-by-step explanation:

the amount of daily deposit of pollutant = 3.2*10−5 g/sq cm=3.2*10−5*104=3.2*10−1 g/sq m3.2*10-5 g/sq cm=3.2*10-5*104=3.2*10-1 g/sq m

the area of the city = 400 sq km =400*103*103 =400*106 sq m=400*103*103 =400*106 sq m

therefore the amount of pollutant that falls on the city in a day 3.2*10−1*400*106=1280*105=1.28*108 gm=1.28*105 kg3.2*10-1*400*106=1280*105=1.28*108 gm=1.28*105 kg

the amount of pollutant that falls on the city in a year = 1.28*105*365=467.2*105=4.672*107 kg

Answer 2

Step-by-step explanation:

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