Question

6) In a frequency distribution, the mid value of class is 17.5 and the width of the class is 3. The lower limit of the class is ​

Answer 1

Explanation:

Mid value =17.5

Width of class=3

lower class limit = mid value - width/2

lower limit = 17.5 - 3/2

lower limit = 16

Answer 2

The lower limit class is 24.75.

Step-by-step explanation:

Given : In a frequency distribution, the mid value of class is 17.5 and the width of the class is 3.

To find : The lower limit of the class ?

Solution :

Let the lower limit of class be x

We are given that the class width is 3.

So, Upper limit of class = x+3

Now we are given that  the mid-value of a class is 17.5.

The mid point formula used is

$\text{Mid value} = \frac{\text{Upper limit} +\text{Lower limit}}{2}$

$17.5= \frac{x+3+x}{2}$

$52.5=2x+3$

$2x=52.5-3$

$2x=49.5$

$x=\frac{49.5}{2}$

$x=24.75$

The lower limit class is 24.75.

#Learn more

In a frequency distribution, the mid-value of a class is 20 and the width of the class is 8. Then the lowee class is

A. 12

B. 24

C. 28

D. 16

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