6) In a GP if T3 = 50 and T6 = 6250 Find:- T10
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Step-by-step explanation:
ar2/ar5=50/6250
a will be cut off and 2 r will also cut off
so, 1/r3=1/125
r = 3√125
r = 5
t10= a( rn-1)/r-1
ar2 =50
a×5×5=50
a=50/25
a=2
now u can solve it by using the formula
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