6. In a hot water heating system, there is a cylindrical pipe of length 28 m and
diameter 5 cm. Find the total radiating surface in the system.
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Answer:
Diameter = 5 cm
Radius = Diameter ÷2=5cm÷2=2.5cm
length of pipe =28m=2800cm
Total Radiating Surface of pipe = Curved surface area + 2 × Area of circular crossection
=2πrh+2πrsquare
=2πr(h+r)=2× 22/7
×2.5(2800+2.5)=44039.28cm square
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