6. In a quadrilateral ABCD, D is equal to 150° and A=B=LC
Find A, B and C.
7. The angles of a quadrilateral are in the ratio of 1:23:4. What is the
measure of the four angles?
8. ABCD is a parallelogram with 2A = 80'. The internal bisectors of B
and C meet each other at O. Find the measure of the three angles of
ABCO
9. The opposite angles of a parallelogram are (3x + 5) and (61 - X).
Find the measure of four angles.
10. Solve the following linear equations
D (x+2) (x+3)+(x-3) (x-2)-2x(x+1)=0
m) 7/x+35 = 1/10
m) (2x-1)/3-(6x-2)/5 = 1/3
it's very important
Answers
Answer:
Step-by-step explanation:
6.) A+B+C+D=360degree
x+x+x+150=360
3x+150=360
3x=360-150
x=210/3
x=70
A=70
B=70
C=70
Q. 6
Answer
Given: Measure of ∠ D = 150° and ∠ A= ∠ B = ∠ C
To find: ∠ A, ∠ B, and ∠ C
Formula Used: Sum of angles of a quadrilateral = 360º
Let ∠ A= ∠ B = ∠ C = x° Sum of the angles of the quadrilateral is 360°.⇒ x° + x° + x° + 150° = 360°⇒ 3x° + 150° = 360°⇒ 3x° = 360° -150° = 210°∴ x =
= 70°
∴ ∠ A = 70°, ∠ B = 70° and ∠ C = 70°
Q.7
Answer
Given, the four angles of a quadrilateral are in the ratio 1:2:3:4
Let the angles be x,2x,3x & 4x.
∴ x+2x+3x+4x=360
⇒10x=360
∴ x=36
0
∴ angles are 36
0
,72
0
,108
0
& 144
0
.
Q.8
answer
Let ∠A be 2x
Let ∠D be 2y
Since AB∥DC , sum of angles on same side of the transversal AD will be 180
o
=>2x+2y=180
o
x+y=90
o
After bisection of angles A and D, we get ∠1=x and ∠2=y as per the given figure.
Now in △AOD, we have
x+y+∠AOD=180
o
90
o
+∠AOD=180
o
=>∠AOD=90
o
Q.9
answer
(3x + 5)° and (61 – x)° are the opposite angles of a parallelogram.
We know that the opposite angles of a parallelogram are equal.
Therefore,
(3x + 5)° = (61 – x)°
3x + x = 61° – 5°
4x = 56°
x = 56°/4
x = 14°
⇒ 3x + 5 = 3(14) + 5 = 42 + 5 = 47
61 – x = 61 – 14 = 47
The measure of angles adjacent to the given angles = 180° – 47° = 133°
Hence, the measure of four angles of the parallelogram are 47°, 133°, 47°, and 133°.
sorry to say not this answer me 10th question