6. In a quadrilateral ABCD, ZA= 60°, ZB=2 ZC= _D. Find the measure of ZB, ZC and ZD.
С
А
75°
O
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0
Answer:
⇒ In quadrilateral ABCD, ∠A = 60
∘
and ∠B:∠C:∠D=2:3:7 [Given]
⇒ Let ∠B,∠C,∠D are 2x
∘
, 3x
∘
and 7x
∘
.
⇒ ∠A+∠B+∠C+∠D=360
∘
[Sum of all angles of quadrilateral is 360
∘
]
⇒ 60
∘
+2x
∘
+3x
∘
+7x
∘
= 360
∘
⇒ 12x
∘
= 360
∘
−60
∘
⇒ x
∘
=
12
300
∘
⇒ x
∘
= 25
∘
⇒ ∠D = 7x
∘
Substitute value of x we get,
⇒ ∠D=7×25
∴ ∠D=175
∘
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0
Answer:
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