Question

6. In a rectangle ABCD, prove that :
AC2 + BD2 = AB2 + BC2 + CD2 + DA2.
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Answer 1

Answer:

Step-by-step explanation:

since angles in a rectangle are right angles

so, in triangle ABC

AC^2=AB^2+BC^2

2(AC^2)=2(AB^2+BC^2)

AC^2+AC^2=AB^2+BC^2+AB^2+BC^2

AC^2+BD^2=AB^2+BC^2+CD^2+AD^2(opposite sides of rectangle are equal and diagonal of a rectangle are equal

Answer 2

Answer:

hope it helps u well

Step-by-step explanation:

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