Question

6) In a right angle triangle PQR, Q = 90
If PQ = 4 cm, QR = 3cm, find PR​

Answer 1

Answer:

Step-by-step explanation:

∆PQR is a right angle triangle

by Pythagoras theorem

(PR)^2=(PQ)^2+(QR)^2

6^2=3^2+((QR)^2

36=9+(QR)^2

36-9=(QR)^2

(QR)^2=27

QR=✓9×3

QR=3✓2

AngleQPR =60° because side opposite to P is ✓3/2 times the hypo(PR)

Angle PRQ=30° because side opposite to R is 1/2 of the hypo(PR)

Answer 2

Answer:

PR IS 5.

Step-by-step explanation:

pythagoren triplet lagao

a2+b2=c2.

ok

so i can say that (pq)2+(qr)2=(pr)2.

(4)2+(3)2=(x)2

16+9=x^2

x=$\sqrt{25}$

x=5=PR.