Question

6. In a triangle ABC, angle B =angle C and angle A= 100°. Find angle B​

Answer 1

Step-by-step explanation:

<B=<C

<A+<B+<C=180

180+<B+<B

2<B=80

<B=40

....<A=100,<B=40,<C=40....

Answer 2

Hello mate..

Question:

In a triangle ABC, angle B =angle C and angle A= 100°. Find angle B.

Answer:

Given:

• ∠B = ∠C
• ∠A = 100°

We Know That:

$\bold{sum \: of \: 3 \: angles \: in \: a \: triangle = 180°}$

∠A + ∠B + ∠C = 180°

100 + x + x = 180° --------(here ∠B = ∠C = x)

100 + 2x = 180

2x = 180 - 100

2x = 80

$\bold{x = \frac{80}{2} }$

Therefore, x = 40

Since, ∠B = ∠C = x; ∠B = 40, ∠C = 40

HOPE THIS HELPS YOU..