Question

6. In a triangle, an exterior angle at a vertex is 95º and its one of the interior opposite
angles is 55°. Find all the angles of the triangle.​

Answer 1

Answer:

Given: ∠ABC=55

∘

and ∠BCO=95

∘

To find: ∠BAC

Solution: By exterior angle sum property of triangle, we have

∠BCO=∠ABC+∠BAC

⇒∠BAC=∠BCO−∠ABC

⇒∠BAC=95

∘

−55

∘

⇒∠BAC=40

∘

Also, ∠BCA+∠BCO=180

o

(straight line)

∠BCA=180−95=85

o