Question

6. In a Wheatstone network ABCD, the resistances in
the four arms are AB = 212, BC = 4 Q2, AD = 1 and
DC = 3 12. A cell of emf 2 V and negligible resistance
is connected between A and C. A galvanometer of
resistance 10 12 is connected between B and D. Find
the current through the galvanometer. ​

Answer 1

Answer:

it needs to have a machine of mathematics or but sorry for this i don't know how to make it solute please mark me brainlist plz