Question

6. In a Young’s double slit experiment, the screen is separated from double-slit by 1.2 m. The distance between the two slits is 0.030 mm. Calculate the distance between adjacent bright fringes. (Given, the wavelength of the light used is λ=560 nm).​

Answer 1

Answer:

Explanation:

Given :

• The screen is separated from double-slit by (D) is 1.2 m.
• The distance between the two slits (d) is 0.030 mm.
• The wavelength of the light used is (λ) = 560 nm.

To Find :

• The distance between adjacent bright fringes.

Fomula to be used :

• x = λD/d

Solution :

★ Converting units,

d = 0.030 mm

⇒ d = 3 × 10^{-5} m

λ = 560 nm

⇒ λ = 5.6 × 10^{-7} m

★Distance between adjacent bright fringes,

x = λD/d

⇒ x = 5.6 × 10^{-7} × 1.2/3 × 10^{-5}

⇒ x = 5.6 × 1.2/3 × 10^{12}

⇒ x = 6.72/3 × 10^{12}

⇒ x = 2.24 × 10^{-12} m

Hence, The distance between adjacent bright fringes is 2.24 × 10^{-12} m.

Answer 2

$\huge\mathcal\colorbox{lightpink}{{\color{black}{★ANSWER★}}}$

$\huge\color{pink}{\textbf{\textsf{GIVEN :-}}}$

• The screen is separated from double-slit by (D) is 1.2 m.
• The distance between the two slits (d) is 0.030 mm.
• The wavelength of the light used is (λ) = 560 nm.

$\huge\color{pink}{\textbf{\textsf{TO FIND :-}}}$

• The distance between adjacent bright fringes.

$\huge\color{pink}{\textbf{\textsf{FORMULA :-}}}$

x = λD/d

$\huge\color{pink}{\textbf{\textsf{SOLUTION :-}}}$

Converting units,

d = 0.030 mm

=> d = 3 × 10^{-5} m

λ = 560 nm

=> λ = 5.6 × 10^{-7} m

Distance between adjacent bright fringes,

x = λD/d

=> x = 5.6 × 10^{-7} × 1.2/3 × 10^{-5}

=> x = 5.6 × 1.2/3 × 10^{12}

=> x = 6.72/3 × 10^{12}

=> x = 2.24 × 10^{-12} m

Hence, the distance between adjacent bright fringes is 2.24 × 10^{-12} m.

Hope it Helps Buddy❤️