Question

6. In an experiment, 0-24 g Mg gives 0-40 g Mgo, in other experiment 0-105 g Mg gives
0-175 g Mgo. Verify the law of constant proportion from these data.​

Answer 1

Explanation:

In first experiment,

2.4 g of iron oxide gave 1.68 g of iron.

Mass of iron oxide =2.4 g

Mass of iron =1.68 g

Mass of oxygen =2.4−1.68=0.72

Ratio of masses of iron and oxygen =

0.72

1.68

=7:3

In second experiment,

Mass of iron oxide =2.9 g

Mass of iron =2.09 g

Mass of oxygen =2.9−2.09=0.81

Ratio of masses of iron and oxygen =

0.81

2.09

=7:3

The same ratio confirms that these experiments clarify Law of constant proportion.