6. In an isosceles triangle, the base angle is twice as large as vertex angle. Find the
angles of the triangle.
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Answered by
10
In an isosceles triangle the base angles are equal.
Let the vertex angle = x
ATQ Base angle = 2x
Three angles : x, 2x, 2x
According to angle sum property the sum of angles of triangle is 180
Then x+ 2x+ 2x = 180
5x = 180
x = 36
Angles of triangle are 36,72,72
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Let the vertex angle = x
ATQ Base angle = 2x
Three angles : x, 2x, 2x
According to angle sum property the sum of angles of triangle is 180
Then x+ 2x+ 2x = 180
5x = 180
x = 36
Angles of triangle are 36,72,72
Hope it helps you
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Answered by
9
Answer:
vertex angle = 36°
each base angle = 2 x 36 = 72°
Step-by-step explanation:
Let the vertex angle be x
base angle=2x
2x+2x+x = 180
5x = 180
x = 180/5
therefore x = 36°
vertex angle = 36°
each base angle = 2 x 36 = 72°
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