Question

6. In each of the following figures, O is the centre of the circle. Find the values of x and
y.
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Answer 1

Step-by-step explanation:

according to Pythagoras theorem,

(T1O)^2+(T1P)^2=(OP)^2

(24)^2+(18)^2=(OP)^2

576+324=900=(OP)^2

OP=x=√(900)=30 cm. so x=30 cm

for triangle POT2 according to Pythagoras theorem,

(OT2)^2+(PT2)^2=(OP)^2

{here OT2=PT1 (according to square rule)}

(PT1)^2+(PT2)^2=(OP)^2

(18)^2+(PT2)^2=(30)^2

(PT2)^2=(30)^2-(18)^2=900-324=576

(PT2)=y=√(576)=24 cm. so y=24 cm

so we get x=30cm and y=24 cm

thanks