Question

6. In Fig. 6.21, AC = AE, AB = AD and angle BAD = EAC. Show that BC = DE​

Answer 1

Answer:

Answer

It is given that ∠BAD=∠EAC

∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides]

∴∠BAC=∠DAE

In △BAC and △DAE

AB=AD (Given)

∠BAC=∠DAE (Proved above)

AC=AE (Given)

∴△BAC≅△DAE (By SAS congruence rule)

∴BC=DE (By CPCT)

Answer 2

Answer:

bc=1/2dc

ac=ae

ab=ad

bad=eac