Question

6. In Fig. 6.37, if Δ ABE ~ Δ ACD, show that Δ ADE ~ Δ ABC.​

Answer 1

REF.Image

Given ΔABE≅ΔACD

To prove ΔADE∼ΔABC

proof it is given that

ΔABE≅ΔACD

Therefore AB= AC [By CPCT] _______ (1)

And AE=AD [By CPCT]

⇒AD=AE __________ (2)

Now Divide (2) by (1) we have

AB

AD

=

AC

AE

_________ (3)

Now in ΔADE & ΔABC

AB

AD

=

AC

AE

[ from equation (3)]

∠A=∠A [ common]

⇒ΔADE∼ΔABC

By SAS criterian of similarity !

Hence proved !

Answer 2

SAS similarty criterion is used