6. In Fig. 7.21. AC = AE, AB = AD and
Z BAD= Z EAC. Show that BC = DE.
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It is given that angle BAD= angle EAC
angle BAD +angle DAC = angle EAC +angle DAC [add angle DAC on both sides]
: angle BAC = angle DAE
In triangle BAC and triangle DAE
AB= AD (Given)
angle BAC = angle DAE(Proved above)
AC =AE (Given)
: triangle BAC congrunt to triangle DAE (By SAS congruence rule)
:BC = DE (By CPCT)
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