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In Fig. 9.25, diagonals AC and BD of quadrilateral
ABCD intersect at O such that OB = OD.
If AB=CD, then show that:
(i) ar (DOC)=ar (AOB)
(ii) ar (DCB)=ar (ACB)
(iii) DA|| CB or ABCD is a parallelogram.
[Hint: From D and B, draw perpendiculars to AC.]
Fig. 9.25
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