Question

6. In fig. ABC is a triangle and D, E and F are mid points of AB, BC and CA
respectively, AFE =120°. Find the value of x.​

Answer 1

Answer:

the line joining the md pts of two sides is parallel to the 3rd side

e and f are md pts

⇒EF║AB

WE KNOW THAT CO-INTERIOR ANGLES ARE SUPPLEMENTARY

⇒X+120=180

⇒X=180-120= 60°

Step-by-step explanation:

Answer 2

Answer:

60

Step-by-step explanation:

Given : ABC is a triangle

           Angle AFE = 120

To find : Value of x

Proof : According to the midpoint theorem, the midpoints joining any two sides of the triangle is parallel to the third side and is equal to half of it

this implies that, DF parallel BC and DF= 1/2 BC

                           DE parallel AC and  DE= 1/2 AC

                           EF parallel AB and EF=1/2 AB

now , EF parallel AB and DE is the transversal

then , Angle A and angle F are on the same side of the tranversal which is known as interior angles

We know that , interior angles are supplementary

this implies that Angle A + Angle F = 180

                                      x + 120  = 180

                                                x = 180 - 120

                                                x =  60

Hope it help's you

Thank you