Question

6. In figure, it is given that AB = CF. EF = BD and ZAFE = 2CBD. Prove that
AAFE = ACBD.
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Answer 1

Answer:

Given in figure

AB=CF ........... (1)

EF=BD ........... (2)

∠AFE=∠DBC

Then AF=AB+BF

And BC=BF+CF

As per (1) and (2) we get

BC=BF+AB=AF

Thus in ΔAFE and ΔBDC

BC=AF

EF=BD

∠AFE=∠DBC

∴ΔAFE=ΔCBD .......... [By SAS rule of congruence]