Question

6. In figure, P is the centre and
chord CD chord AB.

Then, prove that:
Z CPA = ZDPB.​

Answer 1

Answer:

CD∥AB(given)

⇒Cp=OP(radius)

⇒AP=PB(radius)

⇒∴∠PCD=∠PAB

⇒PDC=∠PBA

hence,=∠DPB