Question

6. In sulphur estimation, 0.157 g of an organic compound gave 0 4010
sulphate. What is the percentage of sulphur in the compound?​

Answer 1

Here, mass of the substance taken= 0.157g Mass of BaSO4 ppt. formed= 0.4813g 1 mole of BaSO4 is equivalent to 1 g atom of S (137+32+64)= 233g of BaSO4=32g of S 0.4813g of BaSO4 will contain sulphur=32/233*0.4813 % of sulphur in the compound= 32/233*0.4813*100/0.157 = 42.10Read more on Sarthaks.com - https://www.sarthaks.com/70321/in-sulphur-estimation-0-157-g-of-an-organic-compound-gave-0-4813-g-of-barium-sulphate