Question

6, In the adjacent figure, A (1,1) B (5,1) C(3,4) then find the areas of AABC​

Answer 1

Answer:

Given that Area of the Δ APQ = Area of PQCB

That means Area Δ ABC = 2 Area of Δ APQ

Since PQ ∥ BC

Therefore, Δ APQ is similar to Δ ABC

We know that ratio of the areas of two triangles is equal to the square of ratio of their sides in case of similar triangles.

Therefore,

Areaof△ABC

Areaof△APQ

=

AB

2

PA

2

AB

2

PA

2

=

Areaof△ABC

Areaof△APQ

=

2

1

AB

PA

=

2

1

Therefore, PA:AB = 1:

2

Answer 2

Answer:

$6unit^2$

Step-by-step explanation:

Height of the Triangle = 3 unit

Base of the Triangle = 4 unit

∴ Area of the triangle = $\frac{1}{2} * b * h = \frac{1}{2} * 4 * 3 = 6 unit^2$