Question

6. In the adjoining figure, ABC is a right-angled triangle and BDEF is a square.
Find the length of each side of the square il AC - 26 cm and BC = 10 cm.
(Hint: Area of square BDEF-Area of ABC - Area of AEF - Area of DCE)​

Answer 1

Answer:

Step-by-step explanation:

We know that tangent drawn from external point to a circle are equal

So AD=AF=x

Or BD=BE=y

And CF=CE=z

Now, AB=AD+DB=x+y=12 cm ...(1)

Or BC=BE+EC=y+z=8 cm ...(2)

And AC=AF+CF=x+z=10 cm ...(3)

Adding the above three equation, we get

2(x+y+z)=12+8+10=30 cm

Or x+y+z=15 cm

As per equation (1),

x+y=12 cm

Then, z=15−10=5 cm =CF

As per equation (3),

x+z=12 cm

Then, y=15−12=3 cm =BE

As per equation (2),

y+z=8 cm

Then, x=15−8=7 cm =AD