Question

6.
In the adjoining figure, ABCD is a parallelogram
whose diagonals intersect at O. P is a point on the
diagonal AC such that PA : AO = 1: 2. BP meets
DA produced at Q. Then find (i) PQ : QB,
(ii) A(∆PQA) : A(∆PBC), (iii) A(∆PQA) : A(QBCA)
​

Answer 1

Answer :

(i) PQ : QB = 1 : 4

(ii) ar(∆PQA) : ar(∆PBC) = 1 : 16

(ii) ar(∆PQA) : ar(QBCA) = 1 : 15

Refer to the attachment for solutions