6. In the adjoining figure, ABCD is a rectangle whose diagonals AC and
BD intersect at O. If angle AOB = 110º find the measure of:
(0) angle ODA and (ii) angle OCD.
(Hint: angle AOD = (180° - 110°) = 70°.
Since OA = OD, we have angle OAD = angle ODA. AngleCOD = 110° (Why?) and OC = OD, so angle OCD = angle ODC.)
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Answer:
Angle ODA=70°
Angle OCD=110°
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- angle ODA=180°-110°=70°. (linear pair)
- angle OCD=110° (VOA)
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