Math, asked by satishpatelmrt, 4 days ago

6. In the adjoining figure, it is given that CE || BA, ∆BAC = 80° and ∆ECD = 35°. Find (i) ∆ACE, (ii) ∆ACB, (iii) ∆ABC.​

Answers

Answered by anushkapandey90
3

From the question,

CE∥BA,∠BAC=80

o

,∠ECD=35

o

Now,

(i) ∠BAC=∠ACE=80

o

....[∴ Alternate angles]

(ii) ∠ACB,

=∠ACB+∠ACD=180

o

....[∴ Linear pair]

=∠ACB+∠ACE+∠ECD=180

o

=∠ACB+80+35=180

=∠ACB+125=180

=∠ACB=180−115

=∠ACB=65

o

(iii) ∠ABC

Let us consider △ABC,

∠ABC+∠ACB+∠BAC=180

o

=∠ABC+65+80=180

o

=∠ABC+145=180

=∠ABC=180−145

=∠ABC=35

o

Answered by arjitmishra2011
1

Step-by-step explanation:

Solution

verified

Verified by Toppr

From the question,

CE∥BA,∠BAC=80

o

,∠ECD=35

o

Now,

(i) ∠BAC=∠ACE=80

o

....[∴ Alternate angles]

(ii) ∠ACB,

=∠ACB+∠ACD=180

o

....[∴ Linear pair]

=∠ACB+∠ACE+∠ECD=180

o

=∠ACB+80+35=180

=∠ACB+125=180

=∠ACB=180−115

=∠ACB=65

o

(iii) ∠ABC

Let us consider △ABC,

∠ABC+∠ACB+∠BAC=180

o

=∠ABC+65+80=180

o

=∠ABC+145=180

=∠ABC=180−145

=∠ABC=35

o

Similar questions