Question

6) In the adjoining figure OX is perpendicular to a circle of radius 5cm. OX=3cm then the length of the chord PQ is A) 5 cm B) 4 cm C 8 cm D) 10 cm o​

Answer 1

Answer:

THE LENGTH OF THE CHORD PQ IS 8 cm.

Step-by-step explanation:

AS PQ IS A CHORD

THEN OP IS THE RADIUS OF THE CIRCLE,

AND OX IS THE PERPENDICULAR ON PQ,

SO PXO WILL BE A RIGHT ANGLED TRIANGLE.

SO,BY PYTHAGORAS THEOREM,

OP^2=OX^2+PX^2

5^2=3^2+PX^2

25-9=PX^2

16=PX^2

4=PX

AS WE KNOW , THE PERPENDICULAR DRAWN FROM THE CENTER OF THE CIRCLE BISECTS THE CHORD .

SO PQ=2PX

PQ = 2*4

PQ = 8 CM

HOPE THIS WILL HELP YOU

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