Question

6. In the capacitor shown in the circuit is changed to 5 V and left in the circuit, in 12s the charge on the capacitor will become (e = 2.718)​

Answer 1

q = q. ( e^t/c )

c= rc = 6 2 = 12

t = 12 sec

q. = cv = 5* 2 = 10 c

q = 10 e ^ -12 /12

= 10 e^-1 = 10/e C answer