Question

(6) In the figure (2) given below, AF, BE and CD are parallel lines. Given that
AF = 7.5 cm, CD = 4.5 cm, ED -
= 4.5 cm, ED = 3 cm, BE = x and AE = y. Find the values of
x and y.
​

Answer 1

Answer:

The answer is $y=5cm$ and $x=2.8125cm$

Step-by-step explanation:

• Triangles AEF and DEC are similar, so,

$\frac{AF}{CD} = \frac{AE}{ED}$

$y= \frac{7.5}{4.5} \times 3= 5cm$

• Similarly, triangles AEB and ADC are similar, so,

$\frac{AE}{AD} = \frac{BE}{CD}$

$x= \frac{5}{8} \times 4.5= 2.8125cm$

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