Question

6. In the figure, ABCD is a parallelogram
in which angle DAP = 20°, angle BAP = 40° and
angle ABP = 80°. Find angle APD and angle BPC.


plz help me​

Answer 1

Answer:

Step-by-step explanation:

In parallelogram ABCD,

Given : angle DAP = 20

           angle PAB = 40

           angle PBA = 80

To find  : angle APD and angle BPC

Solution:

in a parallelogram opposite sides are parallel

thus, DC parallel to AB and take transversal as PB

angle BPC = angle PBA  (alternate angles are equal when lines are parallel)

angle BPC = 80 degrees

similarly, again taking DC parallel to AB and taking transversal as AP

andle DPA = angle PAB  (alternate angles are equal when lines are parallel)

angle APD = 40 degrees

Answer 2

Step-by-step explanation:

DC||AB AND AP IS TRANSVERSAL OK