Question

6. In the figure, PM = PN, PM I AB and PN I AC.
7. In the figure, AD = BC and AD || BC. Prove that AB=DC​

Answer 1

Answer:

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Step-by-step explanation:

PM+AB(given)

PN⊥AC(given)

ΔANPnadAMP

∠PNA=90∘

∠PMA=90∘

AP=AP(common)

HenceDM=PN