6. In the first container, the concentration of acid is 30%. In the second container, concentration of acid is 50%. One litre of solution is taken from each container and mixed together. Find the percentage of resultant concentration.
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Answered by
7
40% as 0.3mole from first one then 0.5 mole from 2nd one.. Concn=mole/volume of solution
=0.8/2 =0.4M
0.4X100=40%
=0.8/2 =0.4M
0.4X100=40%
nidhibiochemist:
can you explain more
take the percentage as the amount of substance present in the solution
calculate the amount of mole present.. divide it by volm of new soln
msg me if u have any confusion regarding this
Answered by
2
Answer:
40% as 0.3mole from first one then 0.5 mole from 2nd one.. Concn=mole/volume of solution
=0.8/2 =0.4M
0.4X100=40%
Step-by-step explanation:
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