Question

-6. In the given figure, AABC is an equilateral triangle having each sde
equal to 10 em and a PBC is right angled at P in which PB = 8 cm. find the shaded area of region​

Answer 1

Answer

Given, ΔABC is an equilateral triangle the length of whose side is equal to 10 cm, and ΔDBC is right-angled at D

and BD

Area of shaded region = Area of ΔABC− Area of ΔDBC

Answer 2

Answer:

Answer

Given, ΔABC is an equilateral triangle the length of whose side is equal to 10 cm, and ΔDBC is right-angled at D 

and BD=8cm.

From figure:

Area of shaded

Equation (1) implies 

Area of shaded region =43.30−24=19.30

Therefore, Area of shaded region