Question

6. In the given figure, AACB is a right angled triangle at C and CD 1 AB.
If ZB = 40°, then find :
(1) BAC
(ii) ACD
(iii) BCD
40°
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Answer 1

Answer:

Can you upload question with figure?

Answer 2

Answer:

Step-by-step explanation:

give ∠c = 90°

∴∠a=∠b=45°

so,∠a+∠b+∠c=180°

     45°+45°+90°=180°