6. In the given figure, AACB is a right angled triangle at C and CD 1 AB.
If ZB = 40°, then find :
(1) BAC
(ii) ACD
(iii) BCD
40°
Answers
Answered by
0
Answer:
Can you upload question with figure?
Answered by
1
Answer:
Step-by-step explanation:
give ∠c = 90°
∴∠a=∠b=45°
so,∠a+∠b+∠c=180°
45°+45°+90°=180°
Similar questions