Question

6. In the given figure find DCB ifAE || CD.
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Answer 1

Answer:

DCB=30°

Step-by-step explanation:

Draw EF||CD

In triangle BFG

=>20°+x°=50° [Exterior Angle Property]

=>x=30°

Then,

angleEFC=180°-x [Linear Pair]

=180°-30°

=150°

Therefore,

150°+ angleDCB=180° [Co-Interior Angles]

=>DCB=30° (ans)

Please ignore that drawing of mine.

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Answer 2

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