Question

6. In the given figure, P, Q, R and O are four points on a circle. PR and OQ intersect at a
Point S such that ZPSQ= 119° and ZSQR= 13º. Find ZPOQ.

plz answers this question step by step.
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Answer 1

Answer:

Step-by-step explanation:

it is given that angle PSQ = 119 degree

angle PSQ and angle PSO make 180

so  PSQ + PSO = 180

PSO = 180 - 119

angle PSO = 61 degree

angle PSO= angle QSR

by angle sum property

13 + 61 + QSR = 180

QSR = 180 - 74 = 106 degree

angle QRP = angle POQ

angle POQ = 106 degree  

Answer 2

Answer:

106°

Step-by-step explanation:

angle POQ = angle PRQ = x (assume)

angle QSR = 180 - 119 = 61°

x + 13° + 61° = 180°

x = 106° = angle POQ

thus ,angle POQ = 106°