Question

6. In transferring a charge of 3.2 C across a given
resistor, 19.2 J of work is required to be done. What
is the potential difference between the two ends of the
resistor?​

Answer 1

Answer:

We know that potential difference = Work done/Charge moved.

In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.

Thus, the potential difference = v2-V1 = 230-240 = 10 V

Therefore, Work done = Potential difference * Charge moved.

That is, 10 * 5 = 50 Joules.

Hence, the work done in moving a charge of 5 coulombs from a point at 230 volts to another point at 240 volts is 50 J.

Hope it will help you

from Ace7257

Answer 2

Answer:

We know that, V=W/Q

So, V=? , W= 19.2 J , Q= 3.2

Therefore, V = 19.2 / 3.2

V=6V