Question

6.
In triangle PQR, angle R = angle P, PR - PQ = 3 cm, the perimeter of triangle PQR is 15 cm then PR is equal to:
(2) 3 cm
(C) 4 cm
(6) 7 cm
(d) 5 cm​

Answer 1

Answer:

Option (C)

Step-by-step explanation:

∠R = ∠P (given)

∴ PQ = QR ..(i) (angles opposites to equal sides are equal)

Perimeter of ∆ PQR –

PQ + PR + QR = 15 cm ..(ii) (given)

Also, PR - PQ = 3 cm (given)

PR = 3 + PQ ..(iii)

Putting (iii) in (ii), we get

PQ + 3 + PQ + QR = 15

PQ + 3 + PQ + PQ = 15 [using (i)]

3PQ + 3 = 15

3(PQ + 1) = 15

PQ + 1 = 15/3

PQ + 1 = 5

PQ = 5 - 1

PQ = 4 cm

Putting this value in (iii), we get

PR = 3 + 4

PR = 7 cm

Hence, Option (C) is correct.

Answer 2

Step-by-step explanation:

this is the explanation