Question

6. In what ratio does the y-axis divide the join
of A(-5, 3) and B(7, 6)?
.​

Answer 1

Answer:

5:7

Step-by-step explanation:

as y axis divide the line

so, point which divide the line is given by C(0,y)

let the ratio in which it divide be k:1

here, x1=-5, y1=3, x2=7, y2=6

so by section formula ,

x=(mx2+nx1)/m+n-------------i), y=(my2+ny1)/m+n---------ii)

putting x=0, m=k , n=1, x1=-5 and x2=7 in I)

0=(7k-5)/k+1

or, 7k-5=0

or, 7k=5

or, k=5/7

so, the required ratio is 5/7:1

or, 5:7

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Answer 2

Answer:

Let,

The required ratio be K:l.

Then , the coordinates of the point of division are

(7k-5 / k+1 ,6k+3 /k+1 )

But

it is a point on y_ axis on which

x_coordinnate of every point

Therefore,

7k-5/k+1=0

7k-5=0

k=5/7

thus,

the required ratio is

k=5/7

oor

k=5:7